- TOPOLOGICAL OPERATORS IN TOPOLOGICAL SPACES
Shanmugapriya.H a,* and Sivakamasundari.K a
a Research Scholar and Faculty of Mathematics, Avinashilingam Institute for Home Science and Higher Education for Women. Coimbatore, India
a,*shanmugapriyahs@gmail.com
Received: 4 Feb. 2023 / Accepted: 29 May 2023 / Published: 9 July 2023 https://doi.org/10.25271/sjuoz.2023.11.3.1117
ABSTRACT
Operation Approach on a new class of
topological spaces with -open subsets was called a
-open set. In this article, we examined some
new classes of sets via
-open sets on an operation
on
-open sets in topological spaces such as closure,
, limit points, derived sets, neighbourhood,
interior, exterior, boundary and frontier. Some properties of these topological
properties are investigated. Moreover, a new class of set via the operation
on
-open sets called saturated set are defined. Finally, some
relationships among these classes of sets are given and some examples are
illustrated.
KEYWORDS: -open set,
,
-derived sets,
-neighbourhood,
,
-exterior,
-boundary,
-frontier and
-saturated.
.
Semi-open sets were initially
proposed by Levine [8] in 1963. In 1968,Velicko [13] was the first to allude to
the class of -open
subsets of a topological space. In 1979,Kasahara [7] developed the concept of
α-closed graphs of functions and examined the idea of an operation on an
open set τ. In 1982 Mashhour, Abd El-Monsef, and El-Deeb [9] developed the
idea of preopen sets. Ogata [5] changed the designation of the operation α
to operation
on τ
in 1991. In 1993, Raychaudhuri and Mukherjee [10] discovered and explored a
class of sets called
-preopen.
Khalaf and Asaad [1] in 2009 introduced a new concept
-open
sets in topological spaces. Khalaf and Ameen [2] in 2010 introduced the new
class of open sets called
-open
sets in topological spaces. Assad [3] introduced Operation
approaches on
-open
sets and their separation axioms in 2016.Jayashree and Sivakamasundari [6] in
2018 initiated the Operation approaches on δ-open sets. An operation
on the
collection of
-open
subsets of a topological space was introduced by Asaad and Ameen [4] in 2019. Ameen,
Asaad, and Muhammed [14] in 2019 introduced the super class of δ-open
sets. In 2020, Vidhyapriya, Shanmugapriya and Sivakamsundari [12] developed a
new type of open set called
-open
sets by combining the ideas of
-preopen
and
-open
sets. Shanmugapriya, Vidhyapriya and Sivakamsundari [11] in 2021 introduced
a
-open
set as a novel class of operational open sets in topological spaces. Using
-open
sets, here we examined fundamental properties of topological operators: the
-closure,
,
-limitpoints,
-derivedsets,
-neighborhood,
-interior,
-exterior,
-boundary,
-frontier
of a set and
-saturated
sets.
Let be a set and
be topology then
be the topological space. Here
be a subset of the topological space
.
Definition 2.1[8]. A subset is called semi-open if
.
The complement is called a semi-closed set.
Definition 2.2[12].
a. A
-preopen
subset
of a
space
is
called a
-open
set if for all
, ∃ a
semi-closed set F such that
.The
collection of all
-open
sets is denoted by
.
b. The
point in
is
called
-closure
of
iff
, for
every
-open
set
containing
.It is
denoted by
Definition 2.2[11]. An operation on
is a mapping
such that
for every
, where
is the power set of
and
is the value of
under
.
Definition 2.3[11]. Let be a topological space and
be an operation on
. A nonempty set
of
is called a
-open set if for all
, ∃ a
-open set
such that
and
Proposition 2.4[11]. Every -open set is a
-open set.
Proposition 2.3[11]. The union of any class of -open sets in
is
-open.
Definition 2.5[11]. Let be any topological space. An operation
on
is said to be
-operation if for each
and for every pair of
-open sets H1 and H2 such
that both containing
, ∃ a
- open set F containing
such that
.
Definition 2.6[11]. A topological space (Y, τ) with an operation on
is said to be
- regular space if for given
and for each
-open set H containing
, ∃ a
-open set F containing
such that
.
3.1. AND
-CLOSURE OF A SET
Definition
3.1.1. Let be a subset of a topological space
and
be an operation on
. A point
is called
point
of the set
if for all
-open set H containing
,
.The family of
points
of
is called
of
and is denoted by
.
Proposition
3.1.2. Let be a subset of a topological space
and
be an operation on
, then
.
Proof. Consider
let
then by Definition 2.2
, for every
-open set
containing
. Always
, Which gives
. By Definition 3.1.1,
.
Thus,.
Definition
3.1.3. Let be a subset of a topological space
and
be an operation on
. The
-closure of
is defined as the intersection of all
-closed sets of
containing
and it is denoted by
.
-open set in
Proposition 3.1.4.
Let and
be subsets of a topological space
and
be an operation on
, then the following statements are true:
a.
.
b.
.
c.
is a
-closed
set in
and it
is the smallest
-closed
set containing
.
d.
and
.
e.
is a
-closed
set iff
.
f.
is a
-closed
set
iff
.
g.
If , then
and
.
h.
.
i.
.
j.
.
k.
.
l.
.
Proposition 3.1.5.
If is a
-regular space, then
.
Proof. is proved in Proposition 3.1.2.
Let , then ∃ a
-open set H containing p such that
. As
is a
-regular space then by Definition 3.1.4, for all
and for all
-open set
containing
such that
, so
. Hence
.Therefore
.
Proposition
3.1.6. If is a
-operation on
, then
a.
b.
.
Proof. (a) From Proposition 3.1.4 (f) we
have,
.
On the other side, consider
∃ a pair of
-open sets H1 and H2 such
that both containing
,
and
. Now
is a
-operation on
then for all
and ∃ a
-open set F containing
such that
.
So,
but
.Which gives,
.
Yields, .
So, .
Thus,
.
(b) From Proposition 3.1.4 (k)
so it is enough to obtain that
.
Consider, then there exist two
-open sets
and
containing
such that
=
and
=
. As
is a
-operation on
then by Proposition 3.1.2
is a
-open set in Y so
=
. Finally
, thus
.
So
Proposition 3.1.7. Let be a subset of a topological space
and
be an operation on
. Then
, for every
-open set
of
containing
.
Proof. Consider
and suppose
for some
-open set
of
containing
.
Then and
is a
-closed set in Y. Then,
. Thus,
, this is a contradiction. So
for every
- open set G of Y containing
.
To prove the
contrary, if then ∃ a
-closed set E such that
and
.
Then is a
-open set such that
contradicting our hypothesis.
Thus, .
3.2. -LIMIT POINT
Definition 3.2.1. Let P be a subset of a
topological space and
be an operation on
. A point
is called
- limit point of P if for every
-open set G containing
,
.
The family of - limit points of P is called a
-derived set of P and it is denoted by
.
Some properties of -derived set are mentioned in the following propositions.
Proposition 3.2.2. The following properties
hold for any sets P and Q in a topological space with an operation
on
.
a.
b. If , then
.
c. .
d. .
e. .
f. .
Proof. Proof of (a) is obvious.
(b)We have
,
.Then
Hence .
Thus
This example proves that the reverse inequality of (c),(d), (e) and (f) is not true in general.
Example 3.2.3.Consider the space and
and
.An operation
is defined as follows, for every
.
Implies .
For a subset and
therefore,
.
Hence the reverse inequality of (c) is not true.
For a subset and
therefore,
.
Hence the reverse inequality of (d) is not true.
For a subset therefore,
.
Hence the reverse inequality of (e) is not true.
For a subset therefore,
.
Hence the reverse inequality of (f) is not true.
Corollary 3.2.4. Let P be a subset of a
topological space and
be an operation on
. Then
Proof. Let from Definition 3.2.1, for every
-open set
containing
satisfying
, it follows that
. So, the corollary is proved.
3.3.-NEIGHBOURHOOD OF A POINT AND A SET
Definition 3.3.1. A subset N of a topological
space is called a
-neighbourhood of a point
, if ∃ a
-open set G in Y such that
.
The collection of all -neighbourhood is denoted by
Definition 3.3.2. A subset N of a topological
space is called a
-neighbourhood of a set
if ∃ a
-open set G in Y such that
.
Remark 3.3.3.
Let be a
-open set iff it is a
-neighbourhood of each of its points.
Proposition
3.3.4. If E is a -closed subset of a topological space Y and
, then ∃ a
-neighbourhood N of
such that
Proof. Let E be
-closed subset of a topological space Y, then
is
-open set. Let
. By Remark 3.3.3,
is a
-neighbourhood of each of its points.
Finally ∃ a
-neighbourhood N of
such that
which gives that
.
Proposition
3.3.5. For a topological space the following results of
-neighbourhood are true for all
in Y:
a..
b. If , then
.
c. If and
, then
.
d. If and
, then
.
e. If then there exist
such that
and
for all
.
Proof. (a)
Since by definition of -neighbourhood,
which is a
-open set of
such that
implies
is in
for all
.Therefore
.
(b) Let implies
is
-neighbourhood of
, then by definition
.
(c) Let and
.Since
there exists a
-open set
such that
, then
, implies
is a
-neighbourhood of
, that is
.
(d) Let and
, then there exists two
-open sets
and
such that
and
. Then
. Since
is a
-open set we get
is a
-neighbourhood of
. Thus,
.
(e) Let , then there exist a
-open set
such that
.Since
is a
-open set, it is
-neighbourhood of each of its points by
Remark 3.3.3.Thus, there exist a
-open set
such that
and
for all
.
3.4.-INTERIOR
Definition
3.4.1. Let P be a subset of a topological space and
be an operation on
A point
is called
-interior point of
if ∃ a
-open set H containing
, such that
and we denote the family of such points by
.
Proposition
3.4.2. Let be an operation on
, then for a subset
of Y
and
.
Proof. Let , then by Definition 3.4.1, ∃ a
-open set
such that
and
.
.
Let , which is a
-open set by Proposition 2.3 and Proposition 2.5. Finally,
.
So and
.
Proposition
3.4.3. Let be an operation on
, then the following properties holds:
a.
and
b.
is the
largest
-open set
contained in
.
c.
is
-open
set iff
.
d.
If , then
.
e.
.
f.
.
g.
.
Proof. Proof of (a), (b), (c) and (g) are obvious from existing results and definitions.
The following example shows that the reverse inequality of (d), (e) and (f) is not true in general.
Example
3.4.4.Consider the space and
. An operation
is defined as follows, for every
Implies .
For a subset and
and
. Hence
.
Hence the reverse inequality of (d) is not true.
For a subset and
, implies
.
Hence,
.
Thus, the reverse inequality of (e) is not true.
For a subset and
, implies
.
Hence,.
Hence the reverse inequality of (f) is not true.
Proposition 3.4.5.
If is a
-operation on
then for part of subsets
of a space Y,
.
Proof. We have by Proposition 3.4.3(f).
On the other
hand, let implies that,
and
.Then there exists
-open sets
and
containing
such that
and
, so
.Since
is a
-operation, there exists a
-open set
containing
such that
, hence
.
Therefore, .
Proposition
3.4.6. Let be a subset of a topological space
and
be an operation on
, then the following conditions are hold:
a.
.
b.
.
c.
.
-open sets in topological spaces”, International Journal of Applied
Mathematics 32.2 ,259.